LEMNISCATA
Matemàtiques, física, química…
\[P(A \cap B / A \cup B) = \frac{P((A \cap B) \cap (A \cup B))}{P(A \cup B)} = \frac{P(A \cap B)}{P(A \cup B)},\]en ser\[P(A \cup B) = 1 – P(\overline{A \cup B}) = 1 – P(\overline{A} \cap \overline{B}) = 1 – \frac{800}{4000} = \frac{4}{5},\]\[P(A \cap B) = P(A) + P(B) – P(A \cup B) = \frac{2000}{4000} + \frac{2200}{4000} – \frac{4}{5} = \frac{1}{4},\]obtenim\[P(A \cap B / A \cup B) = \frac{1/4}{4/5} = \frac{5}{16}.\]