LEMNISCATA
Matemàtiques
$\lambda =4750\ Å\cdot\frac{10^{-10}\ m}{1\ Å }= 4.75\cdot10^{-7}\ m$
$f= \frac{c}{\lambda}=\frac{3.00\cdot10^8}{4.75\cdot10^{-7}} = 6.32\cdot10^{14}$ Hz
$E = hf = 4.19\cdot^{-19}$ J
$W_0 = hf_0 = 3.15\cdot10^{-15}$ J
$E_c = E-W_0$
$E_c = 4.19\cdot10^{-19}-3.15\cdot10^{-19} = 1.05\cdot10^{-19}$ J
$E_c = q_eV_0$
El potencial de frenada és:
$V_0 = \displaystyle\frac{1.05\cdot10^{-19}}{1.602\cdot10^{-19}} = 0.655$ V